Question

A particle of mass 3 kg moving in a straight line decelerates uniformly from a speed of 40 m/s to 20 m/s in a distance of 300 m. Before it comes to rest, it will travel a further distance pf​

Answer 1

Answer:

100m

Explanation:

First find out acceleration.

v^2 = u^2+2as.

40^2-20^2 = 2*a*300.

a = 4 m/s^2.

Now find s by v^2 = u^2+2as.

Taking v=0, u=20 & a=4.

We get S = 100 m.