A particle of mass 5 x 10⁻⁹ kg is held at some distance from very large uniformly charged plane. The surface charge density on the plane is 4 x 10⁻⁶C/m². What should be the charge on the particle so that the particle remains stationary even after releasing it ?
ε₀ = 8.85 x 10⁻¹² C⁻² m², g = 9.8 ms⁻²
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Dear Student,
◆ Answer -
q = 2.168×10^-13 C
◆ Explanation -
For the particle to remain stationary, its gravitational force should be balanced by electrostatic force.
Fg = Fe
m.g = q.E
m.g = q.σ/2ε₀
q = 2m.g.ε₀/σ
Substitute values,
q = 2 × 5×10^-9 × 9.8 × 8.85×10^-12 / 4×10^-6
q = 2.168×10^-13 C
Therefore, charge on the particle must be 2.168×10^-13 C.
Hope this helps you...
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