Question

a particle of mass 5gm lies in a potential field v=8x²+200 ergs/gm , calculate it's time period​

Answer 1

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Answer 2

Explanation:

Given A particle of mass 5 gm lies in a potential field v=8x²+200 ergs/gm calculate it's time period

• The relation between potential energy and force for a conservative force acting will be
• F = - dU / dx
• So potential energy U = V.m
•                                     = (8x^2 + 200) x 5
•                    
• Differentiating the given equation we get
•                      F = - 16 x 5x
•            Or F/m = - 16 x 5 / 5 x
•                           = - 16 x
• A particle in simple harmonic equation is given by
•               F/ m = - ω^2 x
• Comparing the equation of force we get
•                So ω^2 = 16
•               Or ω = 4 rad/s will be the angular frequency
•     Now frequency ν = ω / 2π
•                                   = 4 / 2 π
•                                                     = 2/π / s
•        Time period = 1/ν
•                              = π / 2
•                              = 1.575 secs

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https://brainly.in/question/9473430