Question

A particle of mass m = 0.5 Kg travels in a straight
line with velocity v = 5x3/2. Find the work-done by
the net force during the displacement from x=0 to
x = 2 m​

Answer 1

Explanation:

dx/dt = 5x^3/2

dx/ x^(3/2) = 5 dt

Integrating,

-2/ x^(1/2) = 5t

x ^ (-1/2) = -2.5 t

x = 1/6.25 t^2

Differentiate 2 times for acceleration.

m × a = Force

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