Question

A particle of mass m and charge q is placed at rest in a uniform electric field and the released the kinetic energy attained by the particle after moving a distance y is​

Answer 1

Answer:

E=Fq

∴F=Eq

∴K.E. acquired by the particle

Work done =F×s =Eqy

HOPE IT HELPS U !!

Answer 2

S O L U T I O N

Electric Force on charged particle is given by

F = qE

Kinetic energy attained by particle

= work done

= force × displacement

= qE × y

ALTERNATIVE ______

Force on the charged parties in a uniform electric field is

F = ma = Eq

a = Eq/m _[i]

From the equation of motion we have

v^2 = u^2 + 2ay

v^2 = 0 + 2 × Eq/m × y _[u = 0]

v^2 = 2Eqy/m

Now, the kinetic energy of the particle

• K = 1/2 mv^2

• K = m/2 × 2Eqy/m

• K = qEy

∴ The kinetic energy attained by the particle after moving a distance y is k = qEy !