A particle of mass m and charge q is thrown at a
speed u against a uniform electric field [.
distance it travelled before coming to rest will be
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Answer:
Let a particle of mass m and of charge q travelling against the uniform electric field E then the force experience by the particle is
F=qE
ma=qE
a=qE/m …………(1)
we have:
v2=u2 +2as
0=u2 +2as
s=-u2/2a
from equation (1)
s=-u2/2(qE/m)
s=-u2m/2qE
Therefore the distance travel by the particle before coming to momentary rest is given by -u2m/2qE
Negative sign because the particle is retarding.
Explanation:
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