Question

root 7-1/root7+1 rationalise

Answer 1

$\frac{ \sqrt{7} - 1}{ \sqrt{7} + 1} \\ \\ = > \frac{ \sqrt{7} - 1 }{ \sqrt{7} + 1 } \times \frac{ \sqrt{7} - 1 }{ \sqrt{7} - 1 } \\ \\ = > \frac{7 - 2 \sqrt{7} + 1 }{7 - 1} \\ \\ = > \frac{8 - 2 \sqrt{7} }{6} \\ \\ = > \frac{2(4 - \sqrt{7}) }{6} \\ \\ = > \frac{4 - \sqrt{7} }{3}$