Question

A particle of mass m describes a circle of radius r .The centripetal acc. of the particle is 4/r².The momentum of the particle

Answer 1

The momentum of the particle is $\frac{2m}{\sqrt{r} }$.

Centripetal acceleration of the particle is given by the formula

a_c=$\frac{v^{2} }{r}$=4/r^2

On comparing

v=2/√r

Now the momentum of the particle is the product of mass and velocity

P=mv=m*2/√r

Therefore the momentum of the particle is $\frac{2m}{\sqrt{r} }$.

Answer 2

Answer:

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