Question

A particle of mass m is moving along a circle of radius r with a time period T. Its angular momentum is ݎ݉ߨ2) a ܶ ݎ݉ߨ4) b ܶ ݎ݉ߨ2) c ଶ ܶ ݎ݉ߨ4) d ଶ

Answer 1

Answer:

angular momentum=2$\pi$m$r^{2}$ /t

Explanation:

angular momentum=I x w     {I=movement of inertia,w=angular velocity}

given mass as m,radius r,time is T

Time(T) = 2$\pi$/w

from this we can write w=2$\pi$/t

I=m x $r^{2}$

now if we substitute them in the formula we get

angular momentum=m$r^{2}$ x 2$\pi$/t

                                =2$\pi$m$r^{2}$ /t