Question

A particle of mass m is moving in plane along a circular path of radius r. its angular momentum about the axis of rotation is l. the centripetal force acting on the particlenis

Answer 1

angular momentum is given by
m x v x r=l given
so velocity of the particle is l/(m x r)
centripetal force is given by
mv^2/r
so centripetal force is
m(l/mr)^2/r
=l/mr^3

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Answer 2

L^2/mr^3

Step-by-step explanation:

We know,

Angular momentum(L) = mvr

So, v = L/mr

Now,

Centripetal Force(F) = mv^2/r

Put v = L/mr

Then, we get, F = L^2/mr^3