Question

A particle of mass m is moving in the y-z plane with a velocity v0 along the straight line AB. The angular momentum of particle with respect to origin 0​

Answer 1

Answer:

L

=

r

×

P

or

L

=

r

×m

V

Where

V

is velocity vector and we know that it is same at both points A and B .

r

is perpendicular vector on the velocity vector from origin that is perpendicular on line AB so

r

is also same in both cases .

So L

A

=L

B

Answer 2

Explanation:

The angular momentum of particle at A(La) = The angular momentum of particle at B(Lb)

Angular momentum defines L = r × p = rmvsin∅(-k)

The magnitude of L from the above formula can be L = mvrsin∅ = mvd

d is the closest distance of the particle from the origin

The distance of points A and B from the otigin is same which results in the same angular momentum.So La = Lb