A particle of mass m is moving with speed v collides elastically with another particle of mass 2m. Find the speed of smaller mass after head-on collision? A) V/3 B) -(V/3) C) 2V/3 D) -(2V/3)
Answers
Answer :
◈ We know that, coefficient of restitution for elastic collision = 1
➝ e = (v₂ - v₁) / (u₁ - u₂)
➝ e(u₁ - u₂) = (v₂ - v₁)
➝ 1(v - 0) = v₂ - v₁
➝ v₂ = v + v₁ ...... (I)
◈ Linear momentum is conserved during any kind of collision
➝ m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
➝ mv + 2m(0) = mv₁ + 3mv₂
➝ mv = mv₁ + 2m(v + v₁) [Eq. (I)]
➝ v = v₁ + 2v + 2v₁
➝ v - 2v = 3v₁
➝ v₁ = -v/3
Hence, option (B) is the correct answer!
Given :
- A particle of mass m is moving with speed v
- Another mass 2m , which is intallty at rest position
- Collision between m and 2m is elastic
To find :
The speed of smaller mass after head-on collision .
Theory :
• Cofficient of Restitution :
•Collision types :
1) Perfectly elastic collision
- In addition to Momentum , K.E also be conserved.
- e=1
2) Inelastic collision
- K.E after collision < K.E before collision
- 0<e<1
3) Perfectly elastic collision
- Maximum loss of K.E
- e=0
Solution :
We know that :
Since , collision is elastic , thus e= 1
and 2m mass is initially at rest.
here (given )
Since , there is no force then ,
Now , Multiply equation (1) by 2 then,
Now subtract equation (1) form (3) then ,
Therefore, The speed of smaller mass after head-on collision is -v/3
Correct option b)
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More About the topic :
Collision :
It is a phenomenon in which very large force acts for a very short interval of time.