Question

A particle of mass m is projected at an angle alpha to the horizontal with an initial velocity u. The work done by gravity during the time it reaches its highest point is

Answer 1

Answer:

Work done by gravity when the object reach to its maximum height is given as

$W = -\frac{mu^2 sin^2\alpha}{2}$

Explanation:

As we know that work done against the gravitational force is given by

$W = mgH$

here we know that work is to be calculated from ground to the position when it reach to maximum height

So maximum height is given as

$H = \frac{u^2 sin^2\alpha}{2g}$

now from above formula work done against gravity is given as

$W = mg(\frac{u^2 sin^2\alpha}{2g})$

so work done by the gravity is given as

$W = -\frac{mu^2 sin^2\alpha}{2}$

#Learn

Topic : projectile motion

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