Physics, asked by harry259259, 1 year ago

A particle of mass M is projected with initial velocity u at an angle teeta to horizontal. the top of the gravity of projectile at maximum height about the point of projection is​

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Answered by Anonymous
1

L=(mv^3)(sin^2 30^o)(cos30^o)/(2*10) OR

L=mv^3(1/4)(root3/2)/20= mv^3* root3/160 kg m^2/s.

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