Question

A particle of mass m is projected with velocity v making an angle of 45 find change in momentum when it lands

Answer 1

Max height,H= v^2 sin^2(theta) /2g

Velocity at max height=ux=vcos(theta)

Angular momentum =muxH

Substituting the value of theta(45°),

Angular mimentum = mv^3 / g4(×root of 2)

PS: I have used ^ for showing powers and the final formula involves root of 2 in the denominator which is further multiplied by 4 and ‘g’ value.