Question

A particle of mass m is thrown horizontally from the top of a tower and another particle of mass 2m is thrown
vertically upward. The acceleration of centre of mass is
(1)g
(2)9g÷3
(3)2g÷3
(4)g÷2​

Answer 1

Answer:

In order to calculate the acceleration of the centre of mass of this type of particles system, you can follow this method .

Acceleration will be given by

acc. = (m1*a1 + m2*a2)/(m1 + m2)

[This equation can be used for "n" numbers of particles]

We will consider downward direction as positive.

Therefore,

acc. = (m*g +2m*g)/(m+2m)

=>acc = g

The answer is acceleration of centre of the mass is "g".