Physics, asked by ramsha21, 1 year ago

A particle of mass m is thrown horizontally from the top of a tower and another particle of mass 2m is thrown vertically upward. The acceleration of centre of mass is what?

Answers

Answered by Rohan1155

405

I have solved it. See the photo. I have given the concept too.

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ramsha21: thnku but the answer is supposed to be only g. maybe its the sign convention

Rohan1155: yes .I have taken the downward direction to be negative and upward direction to be positive. As gravity acts downward, so according to my sign preference answer came out -g. If u consider the magnitude, answer is g irrespective of direction.

Answered by sawakkincsem

109

Data:
Mass of first particle = m₁ = m
Mass of second particle = m₂ = 2 m
Acceleration of center of mass = ?
Solution:
Acceleration of both particles is the same which is equal to the acceleration due to gravity.
So,
a₁ = a₂ = g
Acceleration of center of mass = a₍cm₎ = ( m₁a₁ + m₂a₂ ) / m₁+ m₂
Acceleration of center of mass = a₍cm₎ = ( m g + 2 m g ) / m + 2m
Acceleration of center of mass = a₍cm₎ = 3 m g / 3 m
Acceleration of center of mass = a₍cm₎ = g
which is the required answer.
Hopefully it helps. Thanks.

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