A particle of mass m moves in the XY plane with a velocity v along the straight line AB. If the angular momentum of the particle with respect to origin O is LA when it is at A and LB when it is at B, then :
Answers
Answered by
0
Answer:
L
=
r
×
P
or
L
=
r
×m
V
Where
V
is velocity vector and we know that it is same at both points A and B .
r
is perpendicular vector on the velocity vector from origin that is perpendicular on line AB so
r
is also same in both cases .
So L
A
=L
B
Option C
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