Question

alkaline earth metal (A), belongs to 3rd period reacts with oxygen and nitrogen to form compound (B) and (C) . it undergoes metal displacement reaction with AgNO3 solution to form compound (D) . indentify A,B,C and D

Answer 1

Answer:

A sodium

B sodium oxide

C sodium nitride

D sodium nitrate

Answer 2

A=Mg

B-Magnesium oxide

C-Magnesium nitride

D-Magnesium nitrate

Explanation:

Alkaline earth metal A=Mg which belongs to 3rd period

$2Mg(s)+O_2(g)\rightarrow 2MgO$

When magnesium react with oxygen then it magnesium oxide.

$6Mg+2N_2\rightarrow 2Mg_3N_2$

When magnesium react with nitrogen then it form magnesium nitride.

When magnesium undergoes displacement reaction with $AgNO_3$

$Mg+AgNO_3\rightarrow MgNO_3+Ag(s)$

Then, it form Magnesium nitrate.

Therefore,

A=Mg

B-Magnesium oxide

C-Magnesium nitride

D-Magnesium nitrate

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https://brainly.in/question/2459399:answered by kingofself