A particle of mass m moves on the path given by r=ia.coswt+j.bsinwt.calculate thetorque about the origin
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A particle is moving on the circular path. So, as per the equation of Circular path the Radius of the circle will be Root a^2+b^2.
So,
Torque = F x R
Torque = mg x Root a^2+b^2
Be Brainly
So,
Torque = F x R
Torque = mg x Root a^2+b^2
Be Brainly
ashu2147483647:
shouldn't we give the answer in vector form?
Why not
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may be the answer to the question is this ...
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