A particle of mass m moves with constant speed v on a circular path of radius r. Find magnitude of average force on it in half revolution.
Answers
Answered by
749
Change in momentum= final momentum-initial momentum
=mv - (-mv)
=2mv
time taken= distance/speed
=pi r/v
average force = 2mv² / pi r
=mv - (-mv)
=2mv
time taken= distance/speed
=pi r/v
average force = 2mv² / pi r
Answered by
215
" Given : with the values, you have to derive formula and apply to get answer. Change in momentum= final momentum-initial momentum
=mv - (-mv)
=2mv
time taken= distance/speed
=pi r/v
average force = 2mv² / pi r
therefore student can simply check out details and collect right ideas of them with out meeting any risk and trouble of it.
"
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