A particle of mass m moving eastward with a speed v collides with another particle of same mass moving northward with same speed v . the 2 particles coalesce on collision. the new particle of mass 2m will move in the north east direction with what velocity ??
Answers
Answered by
56
This is a question on resultant vector.
These particles are moving perpendicular to each other.
The figure of their motion is a right angled triangle.
The resultant velocity is the hypotenuse of the triangle formed.
The triangle is of base v and height vV.
By pythagoras theorem the hypotenuse is :
Hyp = √(v² + v²) = √2v² = v√v
The velocity is thus :
= v√2
alliamalik6:
I think your answer is not correct.
Initial momentum pf system :
Answered by
171
I hope this help!
Answer is given below plzz check it.
Attachments:
Similar questions