Question

A particle of mass m moving with velocity v collides perfectly elastically with a particle of mass 2m at rest . loss of kinetic energy in collision will be​

Answer 1

Answer:

Let velocity of system of particles after collision is v.

By law of momentum conservation.

μ=3mv

⇒v=u/3

Now, loss of kinetic energy =(Ki − Kf)

⇒ΔK=(1/2)μ^2 − (1/2)3m[u/3]^2

⇒ΔK=(1/2)μ^2−(1/6)μ^2

⇒ΔK=(1/3)μ^2