Question

A particle of mass m moving with velocity v collides with another particle of mass 4m which was at rest. After collision both particle sticks together and starts moving with a velocity_________.

Answer 1

Answer:

the answer of this question is v/5

Explanation:

use the principle of conservation of momentum

Answer 2

Answer:

The velocity after collision both particle sticks together and starts moving is $\dfrac{v}{5}$.

Explanation:

Given that,

Mass of particle = m

Velocity = v

Mass of another particle = 4 m

We need to calculate the velocity after collision

Using conservation of momentum

$m_{1}u_{1}+m_{2}u_{2}=(m_{1}+m_{2})v$

Where, m₁ = mass of particle

m₂ = mass of another particle

u = initial velocity

v = final velocity

Put the value into the formula

$mv+0=(m+4m)v'$

$v'=\dfrac{mv}{5m}$

$v'=\dfrac{v}{5}$

Hence, The velocity after collision both particle sticks together and starts moving is $\dfrac{v}{5}$.