Question

A particle of mass M starting from rest, undergoes uniform acceleration.If the speed acquired in time T is V.Find the power declined to the particle.

Answer 1

we know,
power=work/time
=force×dislacement/time
=force×velocity

given,
mass=M
speed acquired in T seconds=V

V=u+at
u=0
V=at
a=V/T

power=mass×acceleration×velocity
=M×V/T×V
=MV^2/T

Answer 2

Answer:

Total power delivered is average power or integral of power delivered from t = 0 to t = T or from velocity = 0 to velocity = V

Now initial velocity = 0, and Final velocity = V. As the acceleration is constant, Average velocity = (0 + V)/2 = V/2

Therefore, Total Power delivered = MV^2/(2T)

Explanation:

In the given solution last step gives instantaneous power delivered. Rest is OK