A particle on a straight line in such a way that it covers 1st half distance with speed 3 m/s and next half distance in 2 equal time intervals with speeds 4.5 m/s and 7.5 m/s respectively. Find average speed of the particle.
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Avg.speed =total distance /total time taken
Avg. Speed in 2nd half=(sT +ST)/2T
= (4.5T+7.5T)/2T
=6m/s
Total avg.Speed = D/(d/2)/3+(d/2)/6
=12D/3D
=4m/s
Avg. Speed in 2nd half=(sT +ST)/2T
= (4.5T+7.5T)/2T
=6m/s
Total avg.Speed = D/(d/2)/3+(d/2)/6
=12D/3D
=4m/s
Anonymous:
answer is 4 m/s
no you see
yes now its right thanxxxxx brother.........
wlcm
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