A particle P is held at rest at a fixed point and then released. P falls under gravity until it reaches the point A which is 1.25 m below O. Find the speed of P at A and the time taken for P to reach A
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Answer:
U=0
S=1.25m
We know
S=Ut+1/2at^2
1.25=0+1/2gt^2
t=0.5secs
Speed at A=V
V=U+at
V=0+g0.5
V=5 m/sec (if g=10m/sec^2)
Explanation:
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