Physics, asked by yasili, 9 months ago

A particle P of mass 0.4 kg is moving under the action of a single force −→F (in Newtons). At time t (in seconds), the velocity of particle P is given by v = (6t + 4)−→i + (t 2 + 3t) −→j (m/s). When t = 0 s, P is at the position −→O = (–3 −→i + 4−→j ) m. When t = 4 s, P is at the point S. (a) Calculate the magnitude of F when t = 4 s. (b) Calculate the distance OS.

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Answered by Anonymous
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A particle P of mass 0.4 kg is moving under the action of a single force −→F (in Newtons). At time t (in seconds), the velocity of particle P is given by v = (6t + 4)−→i + (t 2 + 3t) −→j (m/s). When t = 0 s, P is at the position −→O = (–3 −→i + 4−→j ) m. When t = 4 s, P is at the point S. (a) Calculate the magnitude of F when t = 4 s. (b) Calculate the distance OS.

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