Question

A particle passes a given point moving downwards
with a velocity of 50 m/s. How long before this was
it moving upwards at the same rate?
(1) 12 s
(2) 18.2 s
(3) 10.2 s
(4) 15.4 s​

Answer 1

Answer:

hey mate your answer is (10.2) s

Explanation:

1)v =u+at

.at maximum height velocity is u=0

a=+9.8m/s² acc. due to gravity

. v=50m/s given

. 50=0+9.8t

. t1=5.10

2)when it throw vertically upward

u=50

a=-9.8m/s²

v=0

0=50+(-9.8t)

t2=5.10

so, time when it thrown vertically upward with same speed is =t1 +t2. = = 10.2s

i hope it will help u plz mark it as brainliest answer ☺☺☺☺