A particle performing SHM amax =24m/sec2 ,Vmax=16m/s find the amplitude of particle please answer quickly phy class 11
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Max acceleration = A*omega^2
24 = A*omega^2
And , max velocity = A*omega
16 = A*omega
Dividing
24/16 = Omega^2 / Omega
Omega = 3/2
Now, Amplitude = Max v / Omega = 16/3/2 = 32/3 metres.
24 = A*omega^2
And , max velocity = A*omega
16 = A*omega
Dividing
24/16 = Omega^2 / Omega
Omega = 3/2
Now, Amplitude = Max v / Omega = 16/3/2 = 32/3 metres.
dhruvsh:
avg speed = 4A / 2π / omega
Sir in term of vmax
So, Avg speed = 4*A*omega / 2π
and A*omega is vmax
So avg speed = 2vmax / π
That's all sir
is this one clear?
.....
Ok sir
?,
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