Physics, asked by airanvaibhav4215, 11 months ago

A particle performing shm with a frequency of 5 hz and amplitude 2 cm is initially in the positive extreme position .

Answers

Answered by jangra23

3

w=2πf=24π rad/sec

A=4cm;x=2cm

x=Asinϕ

2=4sinϕ

Thus ϕ=π6

Thus

x=0.04sin(24πt+π6)

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