Question

A particle performs SHM and the equation of motion of the particle is given as y = 5sin(wt) + 5 sin (wt + 557), then amplitude of the SHM is

a. 5

b. 5√2

c. 5√3

d. 10​

Answer 1

Answer:

(a) 5

Explanation:

From the equation we can see that A = 5