Physics, asked by fardoushossain01, 1 month ago

A particle performs SHM is given by the equation = 20 ( + ), if the time period is 30
and the particle has a displacement of 10 at = 0,
Find (i) epoch,
(ii) the phase angle
at = 5 and
(iii) the phase difference between two positions of the particle 15 seconds
apart.

Answers

Answered by skmuffiskmuffi
0

Explanation:

Correct option is

B

π/10

y=10sin(20t+

3

π

)

Comparing with below equation,

y=Asin(ωt+ϕ) where ω=angular velocity=20

Time period T=

ω

=

ω

=

10

π

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