A particle possess two velocities at the same time , one 4m/s due south and the other 2√2 m/s due North -East . Find magnitude and direction of resultant velocity.
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2✓2 m/sec is the magnitude of the the vector and the direction is south east.
Explanation:
- the image of the resultant forces are given below. In the image which is given below there is a force of 2√2 which acts on the north east direction. Hence there is a resultant force of 2 metre per second on each of the north and the east direction.
- Hence the north and south direction being opposite to each other nullify
resulting in the formation of 2 metre per second vector both on the east and the south direction. Hence the the magnitude and direction of the velocity vector can be calculated
To know more,
unit vector in the direction of 4i+4j-2k is ? - Brainly.in
https://brainly.in/question/6789082
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