Question

A particle projected at some angle with velocity 50 m per second crosses a 20 minute walk after force against all the time

Answer 1

Hello!

• Sʸ = 20 m
• u = 50 m
• t = 4 s
• Uʸ = vsinA
• g = 10 ms⁻² 

Then,

Sʸ = Uʸ - $\dfrac{\sf 1}{\sf 2}$ gt​²

⇒ 20 = 50 × 4sinA - $\dfrac{\sf 1}{\sf 2}$10 × 4²

⇒ 20 = 200sinA - 80

⇒ 200sinA = 100 ⇒ $\bf{sinA}$ = $\dfrac{\sf 1}{\sf 2}$

∴ $\boxed{\sf A = \sf 30^{\circ}}$

Cheers!

Answer 2

Answer:

y=Uy*t-1/2gt^2

20=50sintheta*4-1/2*10*(4)^2

20=200sintheta-80

Sin Theta=100/200

Sin Theta=1/2

Theta=30°

Hope it will help you

Mark the brainliest