A particle start from rest has a velocity that increases linearly with time that is v=kt where k is 2m/s2 what will be the distance covered in first three second of its motion
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Hey,
Answer : 9 m
dS=ktdt
S=12kt2
=12×2×3×3m=9m
=9m.
HOPE IT HELPS YOU:-))
Answer : 9 m
dS=ktdt
S=12kt2
=12×2×3×3m=9m
=9m.
HOPE IT HELPS YOU:-))
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