Physics, asked by kumarnitin98762, 1 year ago

a particle start from the origin, goes along x-axis to the point(10m,0) and then returns along the same line to the point(-10m,0).the distance and displacement of the particle during the trip are

Answers

Answered by Shiv4225
125
HEY !! HERE IS YOUR ANSWER ##

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kumarnitin98762: ans 30m,0
Shiv4225: now check
kumarnitin98762: how third 10
Shiv4225: because body is moving backward negative direction so from initial point body moves -10 m backwards
Shiv4225: from origin
kumarnitin98762: distance 10+10+10 this last 10 how and displacement 10 - 10-10 this last( - 10) how
kumarnitin98762: distance 10+10+10 this last 10 how and displacement 10 - 10-10 this last( - 10) how
Shiv4225: distance can never be -ve but displacement can be +ve,-ve or zero
Shiv4225: distance is total distance travelled by the body whereas displacement is the distance between initial and final position
Answered by CarliReifsteck
68

Answer:

The distance and displacement of the particle during the trip are 30 m and -10 m.

Explanation:

Given that,

A particle start from the origin, goes along x-axis to the point (10m,0) and then returns along the same line to the point (-10m,0).

We need to draw the figure.

We calculate the distance

A particle moves 10 meter from the origin O to A along the x axis and then along the same line.

Now, a particle moves 10 m from A to O and 10 m O to B

The total distance is

d =10+10+10=30\ m

The displacement is the shortest distance between starting point and end point.

D = -10\ m

Hence,  The distance and displacement of the particle during the trip are 30 m and -10 m.

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