Question

a particle start moving from +ive x direction with initial velocity of 10 m/s with acccleration 2m/s2 but -ive direction distance covered in 12 sec is

Answer 1

s =ut +(1/2)at²
s=10×12+1/2×2×(12)²
s=120 +144
s=164 m

Answer 2

Hi friend,

To find distance we know that

S=ut +0.5 at²

S=10×12+1/2 ×2×(12)²

S=264 m.

Hope this helped you a little!!!