A particle started with initial velocity u and moving with uniform acceleration a the change of velocity it will gain in the nth second of its journey is
Answers
Answer:
v= u +at
Explanation:
v is final velocity
Answer: Assuming the nth second of the journey..
Distance travelled in nth second of uniformly accelerated motion =
Sn = u+a/2(2n-1)
where u is the initial velocity and a the uniform acceleration of the body.
The sum of distances travelled in T th & (T+1) th second = 100 cm
Therefore,
ST +ST+1 =100
If the particle is moving with initial velocity U and uniform acceleration A, distance travelled by the particle in Tth second will be -
100 = s(t-th) + s(t+1th)
100 = u + a(2t - 1)/2 + u + a(2t + 2 - 1)/2
100 = 2u + a(2t - 1)/2 + a(2t + 1)/2
100 = 2u + (a/2)(2t - 1 + 2t + 1)
100 = 2u + (a/2)(4t)
100 = 2u + a(2t)
100 = 2u + 2at
100 = 2(u + at)
50 = u + at
50 = v
Therefore, the velocity after t seconds is 50cm/s.
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