A particle starting from rest moves along a straight line with constant acceleration.uf it takes 5.0s to reach the speed of 18.0km/h find (a) the average velocity during this period,and (b)the distance travelled by the particle during this period.
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Answer:
Step-by-step explanation:
18 km/hr=5m/s
acceleration=v-u /t
=1m/s²
distance=1/2 1 × 5²
=12.5 m/s
average velocity=12.5/5
=2.5 m/s
aaryandagiya007:
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