Physics, asked by saniya141wilson, 3 months ago

A particle starting from rest, then uniformly accelerated distance x in first two seconds and a distance
y in next two seconds, then
A) y = x
B) y = 2x
C) y = 3x
D) y = 4x
E) y = 9x​

Answers

Answered by jayaramanjyothi66
0

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Answered by rejimolv1
1

Answer:

answer is C

distance travelled in first 2s

=1/2 ×4a ,u=0

distance travelled in next 2s

=s4-s2

=1/2a (4^2-2^2)

=12×a/2

y/x=(12a/2)/(4a/2)

i.e., y=3x

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