A particle starting from rest, then uniformly accelerated distance x in first two seconds and a distance
y in next two seconds, then
A) y = x
B) y = 2x
C) y = 3x
D) y = 4x
E) y = 9x
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Answered by
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Answer:
answer is C
distance travelled in first 2s
=1/2 ×4a ,u=0
distance travelled in next 2s
=s4-s2
=1/2a (4^2-2^2)
=12×a/2
y/x=(12a/2)/(4a/2)
i.e., y=3x
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