A particle starting from rest undergoes a rectilinear motion with acceleration a. The variation of a with time t is shown below. The maximum velocity attained by the particle during its motion is. (a=10m/s2 And t=12s)
Answers
Answered by
70
Hey there,
According to 1st law of motion
v=u+at
Since u=0 m/s as it start from rest
a=10 m/s²
t=12 s
v=0+(12)(10)
120 m/s
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According to 1st law of motion
v=u+at
Since u=0 m/s as it start from rest
a=10 m/s²
t=12 s
v=0+(12)(10)
120 m/s
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Answered by
20
As it is given in the question that that the particle starts its motion from rest position. Hence its initial velocity must be zero. We have to find the final velocity when the particle attains an acceleration of 10 m/s² after 12 seconds.
So, we have
Vi = 0
a = 10 m/s²
t = 12 s
Vf = ?
From the Newton's First Law of Motion:
Vf = Vi + at
Putting the value, we get:
Vf = 0 + (10) (12)
Vf = 120 m/s
So, we have
Vi = 0
a = 10 m/s²
t = 12 s
Vf = ?
From the Newton's First Law of Motion:
Vf = Vi + at
Putting the value, we get:
Vf = 0 + (10) (12)
Vf = 120 m/s
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