Question

A particle starts from a point A(1,2,-1) and reaches a point B(3,2,2). Find the displacement vector AB and it's magnitude?​

Answer 1

Answer:

AB = 2i + 3k

Magnitude= |AB|= 3.605

Explanation:

To find displacement vector subtrat B vector from A.

AB = 3i+2j+2k - ( 1i+2j-1k )

AB = 3i-1i + 2j-2j + 2k-(-1k)

AB = 2i +0j +3k

Magnitude =

$\sqrt{ {2 }^{2} + {3}^{2} }$

$\sqrt{4 + 9}$

$\sqrt{13}$

= 3.605