Question

a particle starts from a point with a velocity of +6.0 m/s and moves with an acceleration of -2.0s².show that after 6s particle will be at the starting point​

Answer 1

$there \: is \: given \: \\ initial \: velocity = 6.0m \s \\ accaleretion = - 2.0 {s }^{2} \\ time = 6s \\ final \: velocity =$

$so \: the \: formula \: is \: \\ \\ v = u + at \\ v = 6.0m \s + ( - 2.0 {s}^{2})6s \\ = 6.0m \s \: - 12.0 {s}^{3} \\ = 6.0m \ {s}^{2}$