Question

a particle starts from rest and experiences a constant acceleration for 6 seconds. if it travel a distance d1 in the first two seconds, a distance d2 in the next two seconds and a distance d3 in the last two seconds, then:

Answer 1

for the first 2 seconds

S =  U t + 1/2 a t² 

d1 = 0 * 2 + 1/2 a 2²
d1 = 2 a

d2 = 0* 4 + 1/2 a 4²  = 8 a

d3 = 1/2 a 6²  = 18 a

d1 : d2 : d3  =  1 : 4 : 9  =  1² : 2² : 3²

Answer 2

s=ut+1/2at²
d1=0+1/2*a*2²
   =2a
d1+d2= 1/2*a*4²
         =8a
d2=6a

d1+d2+d3= 1/2 *a * 6²
               =18a
d3=10a

answer: d1,d2,d3 are 2a, 6a and 10a respectively.