Question

A particle starts from rest and moves along a straight line with constant acceleration. The variation of v with displacements s is ​

Answer 1

Explanation:

V is directly proportional to s

Answer 2

Answer: v = √2as

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We use the relation:

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\:v ^{2} \: - \: u ^{2} \: = \: 2as }} }\\ \\\end{gathered}\end{gathered}$

Body starts from rest and has constant acceleration. Hence,

$\begin{gathered}\begin{gathered}\\ : \implies \displaystyle \sf \: v ^{2} \: = \: 2as\\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\\ : \implies \displaystyle \sf \: v \: = \: \sqrt{2as} \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: v \: = \: \sqrt{2as} }} }\\ \\\end{gathered}\end{gathered}$

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Note-:

• Graph in attachment