Question

a particle starts from rest and moves with an acceleration of 2 metre per second square for 10 seconds after that it travel for 30 seconds with a constant speed and then undergoes retardation of 4 metre per second square and comes back to rest calculate the total distance covered by the particle​

Answer 1

Heya beautiful

Here is ur answer

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Here for the first part of journey u=0 , a=, t =10 sec

v=u + at  => v = 0 + 2 x 10= 20 m/sec

Distance = 0 + 1/2 x 2 x100= 100 m 

As per the question for the second part of journey as the speed is constant a=0 

thus distance s2= 20 x 30 = 600 m

for last part of journey.

u=20 m/sec , v =0 , a= 

 we have  

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Hope this helps u

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