Physics, asked by aneesabhat131, 10 months ago

A particle starts from rest and traverses a distance l with uniform acceleration, then moves uniformly over a further distance 2l and finally comes to rest after moving a further distance 3l under uniform retardation. Assuming entire motion to be rectilinear motion the ratio of average speed over the journey to the maximum speed on its ways.
a. 1/5
b. 2/5
c. 3/5
d. 4/5

Answers

Answered by Anonymous
0

Answer:

AB=L,BC=2L,CD=3L

It starts from rest and accelerates and then remains in uniform velocity and then retards, this means the maximum velocity will be at point B and let it be v

The area under velocity time graph is displacement and hence we have three equations corresponding to regions AB,BC and CD

2

vt

1

=2,vt

2

=2L,vt

3

=3L

t

1

+t

2

+t

3

=+

v

2L

+

v

2L

+

v

6L

=

v

10L

and the average velocity

=

totaltime

totaldisplacement

v

ˉ

=

t

1

+t

2

+t

3

6L

=

5

3v

Hence,

v

v

ˉ

=

5

3

Attachments:
Answered by darshit712
1

Answer:

A particle starts from rest and traverses a distance l with uniform acceleration, then moves uniformly over a further distance 2l and finally comes to rest after moving a further distance 3l under uniform retardation. Assuming entire motion to be rectilinear motion the ratio of average speed over the journey to the maximum speed on its ways.

a. 1/5

b. 2/5

c. 3/5

d. 4/5

Ans I thik c

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