Question

A particle starts from rest at t=0 and moves in a straight line with an acceleration as shown below. The velocity of the particle at t=3 s is



A

2 ms−1

B

0 ms−1

C

6 ms−1

D

8 ms−1



​

Answer 1

The velocity of the particle is 4 m/s.

Explanation:

We are given that:

• Initial time "t1" = 0 s
• Final time "t2 = 3 s

To find: velocity of the particle v" = ?

Solution:

Velocity of the particle at 3s = +4-4

Acceleration of the aprticle=  2 x 3 x 4 times

Now

v = ∫a . dt

v = 4 x 2 = 8 m/s

Now subtract the values

v = 8 - 4 = 4 m/s

Thus the velocity of the particle is 4 m/s.