a particle starts from rest.its acceleration (a) versus time(t) is as shown in the figure.the maximum speed of the particle will be........ options are a.110m/s b.55 c.550. d.660m/s.
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56
Area of triangle =1/2 * 11*10 =55
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Explanation:
Given,
u=0m/s Particle initially at rest
Acceleration, a=
dt
dv
dv=adt
v=∫adt. . . . . . . . .(1)
From the above equation, velocity of the particle is equal to the area under the acceleration-time curve.
From the given acceleration-time graph,
v
max
=
2
1
×base×height
v
max
=
2
1
×11×10
v
max
=55m/s
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